
Consider the following series:
The above series is known as power Series in x.
The power series converges for some values of x and diverges for others.
If the above power series is equal to some f(x) and then for all values of x within the interval of convergence, the function f satisfies the following 3 properties.
a) f is continuous b) f is differentiable c)f is integrable
MacLaurin Series:
This Series can be derived from the first 2 properties of the above Power Series as follows.
If f(x) = a0 + a1x +a2x2 +a3x3 + ...
Then, f'(x) = a1 + 2a2x + 3a3 x2 +4a4x3+ ...
f''(x) = 2a2 + 3.2a3x + 4.3a4 x2 + 5.4a5x3+ ...
f'''(x) = 3.2a3 + 4.3.2a4x + 5.4.3a5 x2 + ...
If x =0, then we have f(0) = a0, f'(0) = a1, f''(0) = 2a2 , f'''(0) = 3.2a3 =6a3
In general, we can write f(n)(0) = n! an
and an = f(n)(0)/n!
Substituting these an values in the equation for f(x), we get Maclaurin Series as follows.
f(x) = f(0) + f'(0)x + {f''(0)}x2/2! +{f'''(0)}x3/3! + ... +{fn(0)}xn/n! + ...